(3x^2+4x-5)(2x+1)=

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Solution for (3x^2+4x-5)(2x+1)= equation: 


Simplifying
(3x2 + 4x + -5)(2x + 1) = 0

Reorder the terms:
(-5 + 4x + 3x2)(2x + 1) = 0

Reorder the terms:
(-5 + 4x + 3x2)(1 + 2x) = 0

Multiply (-5 + 4x + 3x2) * (1 + 2x)
(-5(1 + 2x) + 4x * (1 + 2x) + 3x2 * (1 + 2x)) = 0
((1 * -5 + 2x * -5) + 4x * (1 + 2x) + 3x2 * (1 + 2x)) = 0
((-5 + -10x) + 4x * (1 + 2x) + 3x2 * (1 + 2x)) = 0
(-5 + -10x + (1 * 4x + 2x * 4x) + 3x2 * (1 + 2x)) = 0
(-5 + -10x + (4x + 8x2) + 3x2 * (1 + 2x)) = 0
(-5 + -10x + 4x + 8x2 + (1 * 3x2 + 2x * 3x2)) = 0
(-5 + -10x + 4x + 8x2 + (3x2 + 6x3)) = 0

Combine like terms: -10x + 4x = -6x
(-5 + -6x + 8x2 + 3x2 + 6x3) = 0

Combine like terms: 8x2 + 3x2 = 11x2
(-5 + -6x + 11x2 + 6x3) = 0

Solving
-5 + -6x + 11x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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